That represents an additional reduction of the water temperature that wasn't in those examples. or on theoretical calculations by the methods of statistical physics. You might think this temperature is low in light of our previous examples, but recall that in melting, the ice extracts an extra 333 J/g of energy from the water without a change it its temperature. Equations of state cannot be derived from thermodynamic relations alone but rely. Now let's multiply, distribute, group like terms – just solid algebra moves – and solve for T f.Ĩ2(20) 13,342 167 T_f 837(T_f - 25)
0 Comments
Leave a Reply. |